How many moles of CoO(s) will be formed for every mole of CoCl2⋅6H2O(s)?

1 Answer
Lovecraft
Mar 8, 2016

The ratio is 1:1

Explanation:

Assuming you meant how many moles of CoO will be formed from the reaction of CoCl2 with a strong base such as NaOH, we can start working this out, well, at first we have

CoCl2+NaOH→Co(OH)2(s)+NaCl
(The water was ignored because it's solvent, so, even if we do add it it's not gonna participate in the reaction)

Balancing that equation we see we need to have 2 sodiums in the LHS and 2 chlorides in the RHS, which we can solve by putting a 2 in front of NaOH and NaCl

CoCl2+2NaOH→Co(OH)2(s)+2NaCl

So we know that 1 mole of cobalt (II) chloride makes 1 mole of cobalt (II) hydroxide, next we need to see the dehydration reaction.

Co(OH)2→CoO+H2O

Which, if we check is already balanced, so we can say that 1 mole of cobalt (II) chloride makes 1 mole of cobalt (II) oxide.

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