How many moles of $FeO$ are produced if 8 moles of $SO_2$ are produced in $2CuFeS_2 + 5O_2 -> 2Cu + 2FeO + 4SO_2$ ?

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Answer 1 · 2017-02-06T16:04:51

The mole ratio $FeOdivSO_2=2div4=1div2$ , as you can see from the equation.

So: $8 mol SO_2harr4mol FeO$

Answer 2 · 2017-02-06T16:17:53

$"4 moles of FeO"$

$"In every reaction we can determine amount of reactants and"$ $"products by using ratio formulas."$

#"In this reaction the ratio formula =

$2CuFeS_2 : 5O_2 = 2Cu : 2FeO : 4SO_2$

By solving the ratio we see

$(2 * 2CuFeS_2) : (5/4 * 5O_2) = (2* 2 Cu) : (2 * 2FeO) : (4 * 2 SO_2)$

$(4CuFeS_2) : ( 6.2O_2) = (4Cu) : (4FeO) : (8SO_2)$

Therefore FeO produced is 4 moles

How many moles of FeOFeO are produced if 8 moles of SO_2SO_2 are produced in 2CuFeS_2 + 5O_2 -> 2Cu + 2FeO + 4SO_22CuFeS_2 + 5O_2 -> 2Cu + 2FeO + 4SO_2?