How many moles of gas are in a volume of 63.3 L at STP?
1 Answer
At STP of 273.15 K and 100 kPa, 63.3 L of an ideal gas would contain 2.33 moles.
At STP of 273.15 K and 1 atm, 63.3 L of an ideal gas would contain 2.82 moles.
Explanation:
At STP of 273.15 K
In order to answer this question, divide the given volume by the molar volume of 27.710980 L/mol.
https://en.m.wikipedia.org/wiki/Molar_volume
Just in case your teacher uses the older values for STP, 273.15 K and 1 atm. The molar volume of a gas at this STP is 22.414 mol/L.
https://en.m.wikipedia.org/wiki/Molar_volume
Just as with the previous calculation, divide the given volume by the molar volume of 22.414 mol/L.