How many moles of gas occupy a 3.45-L container at a pressure of 150 kPa and a temperature of 45.6°C?
1 Answer
Explanation:
Your tool of choice here will be the ideal gas law equation, which looks like this
color(blue)(ul(color(black)(PV = nRT)))
Here
P is the pressure of the gasV is the volume it occupiesn is the number of moles of gas present in the sampleR is the universal gas constant, equal to0.0821("atm L")/("mol K") T is the absolute temperature of the gas
Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.
In this case, you have
ul(color(white)(aaaacolor(black)("What you have")aaaaaaaaaacolor(black)("What you need")aaaaa))
color(white)(aaaaaacolor(black)("liters " ["L"])aaaaaaaaaaaaaaacolor(black)("liters " ["L"])aaaa)color(darkgreen)(sqrt())
color(white)(aaacolor(black)("kilopascals " ["kPa"])aaaaaaaaacolor(black)("atmospheres " ["atm"])aaa)color(red)(xx)
color(white)(acolor(black)("degrees Celsius " [""^@"C"])aaaaaaaaaacolor(black)("Kelvin " ["K"])aaaa)color(red)(xx)
This means that in order to use the ideal gas law equation with the given value for the universal gas constant, you must convert the pressure and the temperature of the gas by using the conversion factors
color(blue)(ul(color(black)("1 atm = 760 kPa")))" " and" " color(blue)(ul(color(black)(T["K"] = t[""^@"C"] + "273.15")))
Rearrange the ideal gas law equation to solve for
PV = nRT implies n = (PV)/(RT)
Plug in your values to find -- do not forget the conversion factors!
n = ( 150/760 color(red)(cancel(color(black)("atm"))) * 3.45 color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (45.6 + 273.15)color(red)(cancel(color(black)("K"))))
color(darkgreen)(ul(color(black)("0.026 moles")))
The answer is rounded to two sig figs, the number of sig figs you have for the pressure of the gas.