How many moles of HCl are required to completely neutralize 0.30 moles of $C a {(O H)}_{2}$ $Ca(OH)_2$ ?

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Answer 1 · 2017-11-25T07:46:22

Why $0.60 \cdot m o l$ $0.60*mol$ ....

And how do we know?

Well, we interrogate the stoichiometric equation...

$C a {(O H)}_{2} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + 2 H_{2} O (l)$ $Ca(OH)_2(s) + 2HCl(aq) rarr CaCl_2(aq) + 2H_2O(l)$

Two equiv of $H C l$ $HCl$ are required per equiv $calcium hydroxide$ $"calcium hydroxide"$ ..

What number of $H C l$ $HCl$ molecules are required for equivalence?

How many moles of HCl are required to completely neutralize 0.30 moles of Ca(OH)2Ca(OH)_2?