How many moles of $HNO_3$ will be produced when .51 mol of $N_2O_5$ reacts in the equation $N_2O_5 + H_2O -> 2HNO_3$ ?

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Answer 1 · 2016-05-21T04:54:14

What does the balanced equation say?

It says that $1$ $"mole"$ of dinitogen pentoxide reacts with 1 mole of water to produce $2$ $"moles"$ of nitric acid.

Now you start with a $"0.5 mole"$ quantity of $N_2O_5$ . I think it is pretty clear how much nitric acid you are going to get.

How many moles of HNO_3HNO_3 will be produced when .51 mol of N_2O_5N_2O_5 reacts in the equation N_2O_5 + H_2O -> 2HNO_3N_2O_5 + H_2O -> 2HNO_3?