How many moles of oxygen are present in 33.6 L of the gas at 1 atm and 0°C?

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How many moles of oxygen are present in 33.6 L of the gas at 1 atm and 0°C?

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Answer 1 · 2016-04-25T08:28:02

$1.5$ $1.5$ $m o l$ $mol$ $O_{2}$ $O_2$ gas.

Explanation:

We assume that dioxygen gas behaves ideally. Under the given conditions, an ideal gas has a volume of $22.4 \cdot L \cdot m o l^{- 1}$ $22.4*L*mol^-1$ .

So we simply divide the volume by the molar volume under standard conditions, $22.4 \cdot L \cdot m o l^{- 1}$ $22.4*L*mol^-1$ .

$(33.6*cancelL)/(22.4*cancelL*mol^-1)$ $=$ $?? mol$

How did I know that the molar volume of an ideal gas at $"STP"$ was $22.4*L$ ? You would be given this information as supplementary material in any examination.

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How many moles of oxygen are present in 33.6 L of the gas at 1 atm and 0°C?

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