Question

How many moles of sodium hydroxide contained in 300 mL of a .100M NaOH solution?

Answer 1

`"Number of moles of sodium hydroxide"`

`=300*mLxx10^-3L*mL^-1xx0.100*mol*L^-1`.

Explanation:

`=300*cancel(mL)xx10^-3cancel(L)*cancel(mL^-1)xx0.100*mol*cancel(L^-1)`

`=3.00xx10^-2*mol`