How many moles of $S r {(N O_{3})}_{2}$ $Sr(NO_3)_2$ would be used in the preparation of 2.50 L of a 3.5 M solution?

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Answer 1 · 2018-01-14T23:51:50

$η = 8.8 mol of S r (N O_{3}) 2$ $eta=8.8" mol of " Sr(NO_3)2$

The problem can be directly solved using the standard formula

$Molarity (M) = \frac{(number of moles) (η)}{(Liter solution) (V)}$ $"Molarity"(M)=(("number of moles")(eta))/(("Liter solution")(V)$ , so that

$η = (M) \times (V)$ $eta=(M)xx(V)$

$eta=(3.5mol)/cancel(L)xx2.50cancelL$

$eta=8.8mol$

How many moles of Sr(NO_3)_2Sr(NO3)2Sr(NO_3)_2 would be used in the preparation of 2.50 L of a 3.5 M solution?