How many moles of zinc oxide is produced if 4.44 moles of zinc reacts with excess oxygen?

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How many moles of zinc oxide is produced if 4.44 moles of zinc reacts with excess oxygen?

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Answer 1 · 2016-12-19T20:00:35

Why $4.44$ $4.44$ $m o l$ $mol$ precisely.

Explanation:

As for all these problems, we first need a stoichiometrically balanced equation,

$Z n (s) + \frac{1}{2} O_{2} (g) \to Z n O (s)$ $Zn(s) + 1/2O_2(g) rarr ZnO(s)$

And thus between the oxide and the starting metal, there is clearly $1 : 1$ $1:1$ equivalence. So if there are 4.44 moles of zinc, clearly there are 4.44 moles of oxide. If 10 moles of zinc oxide were produced, then how moles of zinc were used?

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How many moles of zinc oxide is produced if 4.44 moles of zinc reacts with excess oxygen?

1 Answer

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