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How many nitrogen atoms are in a 2.51 mol sample of N_2O?

1 Answer

Aug 28, 2016

$5.02 \times N_{A}$ $5.02xxN_A$ , where $N_{A} = Avogadro's number$ $N_A="Avogadro's number"$

Explanation:

$N_{A} = 6.022 \times 10^{23} \cdot m o l^{- 1}$ $N_A=6.022xx10^23*mol^-1$

Clearly there are $5.02 \times N_{A}$ $5.02xxN_A$ nitrogen atoms in a $2.51 \cdot m o l$ $2.51*mol$ sample. How many oxygen atoms?

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