How many nitrogen atoms are present in a sample of 1,983 hydrogen atoms, if ammonia is a compound consisting of a 1:3 ratio of nitrogen and hydrogen atoms?

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How many nitrogen atoms are present in a sample of 1,983 hydrogen atoms, if ammonia is a compound consisting of a 1:3 ratio of nitrogen and hydrogen atoms?

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Answer 1 · 2014-12-17T13:45:18

The answer is $661$ $661$ atoms of $N$ $N$ .

Since ammonia ( $N H_{3}$ $NH_3$ ) has a $1 : 3$ $1:3$ ratio of Nitrogen to Hydron atoms, and since the number of $H$ $H$ atoms is 1983, the number of $N$ $N$ atoms is

$1983$ $1983$ $H$ $H$ $a t o m s$ $at oms$ $\cdot \frac{1 a t o m N}{3 a t o m s H} = 661$ $* (1 at om N)/(3 at oms H) = 661$ atoms $N$ $N$ .

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How many nitrogen atoms are present in a sample of 1,983 hydrogen atoms, if ammonia is a compound consisting of a 1:3 ratio of nitrogen and hydrogen atoms?

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