How many silver atoms are there in 3.84 g of silver?

1 Answer
anor277
Jul 10, 2016

We know that in 126.94*g of silver there are N_A", i.e. Avogadro's number of silver atoms, "6.022xx10^23" individual silver atoms".

Explanation:

So, we work out the quotient, and multiply by Avogadro's number,:

(3.84*g)/(126.94*g*mol^-1)xx6.022xx10^23*mol^-1

= ??" silver atoms"

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