How much aluminum can be retrieved from 55.6 g of aluminum oxide, Al_2O_3Al2O3?

1 Answer
anor277
Jan 29, 2017

Approx. 30*g30⋅g of aluminum metal

Explanation:

"Moles of alumina"Moles of alumina == (55.6*g)/(101.96*g*mol^-1)=0.545*mol55.6⋅g101.96⋅g⋅mol−1=0.545⋅mol.

Given that each mole of alumina contains 2 moles of aluminum metal, there are 1.09*molxx26.98*g*mol^-1=??g1.09⋅mol×26.98⋅g⋅mol−1=??g

The production of aluminum from alumina is highly energy intensive, even given that aluminum (as Al_2O_3Al2O3) is the third most abundant element in the Earth's crust. The aluminum-oxygen bond is very strong, and much electrical energy must be supplied for reduction.

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