How much of an alloy that is 30% copper should be mixed with 600 ounces of an alloy that is 80% copper in order to get an alloy that is 40% copper?

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Answer 1 · 2016-11-14T19:29:39

The amount is $= 2400$ $=2400$ ounces

Let $x$ $x$ ouncs be amount of the alloy

And the total $= x + 600$ $=x+600$ ounces

Therefore the balance with respect to copper is

$x \cdot 0.3 + 600 \cdot 0.8 = (x + 600) \cdot 0.4$ $x*0.3 +600*0.8=(x+600)*0.4$

$0.3 x + 480 = 0.4 x + 240$ $0.3x+480=0.4x+240$

$0.1 x = 240$ $0.1x=240$

$x = 2400$ $x=2400$ ounces