How much power is needed to accelerate an object with a mass of $4 k g$ $4 kg$ and a velocity of $3 \frac{m}{s}$ $3 m/s$ at a rate of $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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Answer 1 · 2016-06-19T18:43:15

$P = 72 Watt$ $P=72" Watt"$

$P=W/(Delta t)" (definition of power)"$

$W=F*Delta x" (definition of work"$

$F=m*a" (The Newton's second law of motion)"$

$W=m*a*Delta x$

$P=(m*a*Delta x)/(Delta t)$

$(Delta x)/(Delta t)=v$

$P=m*a*v" (definition of velocity)"$

$P:"Power"$

$"m:mass of object ;(4 kg)"$

$a:"acceleration of object ;(6) "m/s^2$

$v:"velocity of object ;(3) "m/s$

$P=4*6*3$

$P=72" Watt"$

How much power is needed to accelerate an object with a mass of 4 kg4kg4 kg and a velocity of 3 m/s3ms3 m/s at a rate of 6 m/s^26ms26 m/s^2?