How much work does it take to push an object with a mass of 1 kg 1kg up a 6 m 6m ramp, if the ramp has an incline of (5pi)/125π12 and a kinetic friction coefficient of 4 4?

1 Answer
Feb 3, 2016

W=117,83592W=117,83592 "Joule"

Explanation:

enter image source here
step:1step:1
"let's convert radian to degree"let's convert radian to degree

theta=180*(5cancel(pi))/(12cancel(pi))=75^o
sin 75=0,966
cos 75=0,259
G=m*g=1*9,81=9,81N

step:2
color(green)(F_1)=G*sin theta=9,81*0,966=9,47616N
color(red)(F_2)=G*cos theta=9,81*0,259=2,54079N
color(red)(N=-F_2)=-2,54079N
color(red)(N) "is the reacting force to" color(red)(F_2)"by acting surface"
color(purple)(F_f)=k*color(red)(N)"(friction force)"
color(purple)(F_f)=4*2,54079=10,16316N
"now let's sum these forces"
sumF=color(green)(F_1)+color(purple)(f_f)
sumF=9,47616+10,16316
sumF=19,63932N

step:3

sumF" is the minimum force that will transport object from"
"the point A to the point B"
W=sumF* Deltax
W=19,63932*6
W=117,83592 "Joule"