How much work would it take to horizontally accelerate an object with a mass of #8 kg# to #3 m/s# on a surface with a kinetic friction coefficient of #6 #?

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Answer 1 · 2017-12-17T19:08:58

The work is #=36J#

The mass of the object is #m=8kg#

The velocity of the object is #v=3ms^-1#

The kinetic energy of the object is

#E=1/2mv^2=1/2*8*3^2=36J#

The work done is equal to the kinetic energy

Therefore,

The work is #=36J#