How to balance complicated chemical equations?

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How to balance complicated chemical equations?

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Answer 1 · 2017-07-29T11:59:30

Every chemical equation balances MASS and CHARGE.......

Explanation:

You gots a metal carbonate, say $Z n C O_{3} (s)$ $ZnCO_3(s)$ :

$Z n C O_{3} (s) + 2 H C l (a q) \to Z n C l_{2} (a q) + C O_{2} (g) ↑ ⏐ + H_{2} O (l)$ $ZnCO_3(s) + 2HCl(aq) rarr ZnCl_2(aq) + CO_2(g)uarr+H_2O(l)$

Are mass and charge balanced here? If they are not then you cannot accept the equation as a representation of chemical reality. And if you start with $10 \cdot g$ $10*g$ of reactant from all sources, you inevitably finish with $10 \cdot g$ $10*g$ product.......

The lesson that I try to reinforce is that $mass and charge are CONSERVED$ $"mass and charge are CONSERVED"$ .

Carbonates (and these are often insoluble salts) react with acids according to the following net ionic equation......

$C O_{3}^{2 -} + 2 H^{+} \to C O_{2} (g) + H_{2} O (l)$ $CO_3^(2-) + 2H^(+) rarr CO_2(g) +H_2O(l)$

You simply have to know these reactions, and how to balance them stoichiometrically.

And likewise for bicarbonates......

$H C O_{3}^{-} + H^{+} \to C O_{2} (g) ↑ ⏐ ⏐ + H_{2} O (l)$ $HCO_3^(-) + H^(+) rarr CO_2(g)uarr + H_2O(l)$

Bicarbonate salts TEND to be soluble. Carbonate salts tend to be insoluble. But this is the province of experiment.

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How to balance complicated chemical equations?

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