How to convert slope intercept $y = - \frac{1}{3} x + 4$ $y = -1/3x + 4$ into standard form?

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How to convert slope intercept $y = - \frac{1}{3} x + 4$ $y = -1/3x + 4$ into standard form?

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Answer 1 · 2015-04-03T20:01:20

Assuming by "standard form" you mean in the form
$a x + b y = c$ $ax + by = c$ for some constants $a, b, c$ $a, b, c$

then $y = - \frac{1}{3} x + 4$ $y=-1/3x+4$
is equivalent to
$\frac{1}{3} x + y = 4$ $1/3 x + y = 4$
or, if you want to avoid fractions
$x + 3 y = 12$ $x +3y=12$

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How to convert slope intercept $y = - \frac{1}{3} x + 4$ $y = -1/3x + 4$ into standard form?

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