How to do order of operations with brackets $2[(9-8)^2+(12-5)^2]$ ?

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Answer 1 · 2016-08-03T12:16:58

$100$

This is all one term, but within thesquare bracket there are two terms which need to be simplified separately.

$2[color(red)((9-8))^2+ (color(blue)(12-5))^2]$

= $2[color(red)((1)^2)+ color(blue)((7)^2)]$

= $2[color(red)1+ color(blue)49]$

= $2 xx50$

= $100$

How to do order of operations with brackets 2[(9-8)^2+(12-5)^2]2[(9-8)^2+(12-5)^2]?