How to do this one?

Question

How to do this one?

1 Answer

Impact of this question

989 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-15T19:52:14

$19.53 feet to 2 dec. places$ $19.53" feet to 2 dec. places"$

Explanation:

$this is a right triangle trig. problem$ $"this is a "color(blue)"right triangle trig. problem"$

$in relation to the given angle of 52^{\circ}$ $"in relation to the given angle of "52^@$

$the telephone pole is the side opposite$ $"the telephone pole is the side "color(blue)"opposite"$

$and base of pole to guy rope is the adjacent$ $"and base of pole to guy rope is the "color(blue)"adjacent"$

$let the distance of pole to guy rope anchor be x$ $"let the distance of pole to guy rope anchor be "x$

$∙ x {tan 52}^{\circ} = \frac{opposite}{adjacent} = \frac{25}{x}$ $•color(white)(x)tan52^@="opposite"/"adjacent"=25/x$

$\Rightarrow x {tan 52}^{\circ} = 25 \leftarrow cross-multiplying$ $rArrxtan52^@=25larrcolor(blue)"cross-multiplying"$

$\Rightarrow x = \frac{25}{{tan 52}^{\circ}} \approx 19.53$ $rArrx=25/(tan52^@)~~19.53$

Science

Math

Humanities

... and beyond

How to do this one?

1 Answer

Explanation:

Related questions

Impact of this question