How to do this one?

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1 Answer
Dec 8, 2017

pi/3, pi, (5pi)/3

Explanation:

3cos(x2)3sinx=0.
Replace sin x by 2sin(x2).cos(x2)
3cos(x2)6sin(x2).cos(x2)=0
3cos(x2)(12sin(x2))=0
Either one of the factors should be zero.

A. cos(x2)=0. Unit circle gives 2 solutions:
x2=π2 and x2=3π2 -->
a.x2=π2 --> x=π
b. x/2 = (3pi)/2 --> x=3π (rejected because outside of range)
B. 12sin(x2)=0
sin(x2)=12
Trig table and unit circle give 2 solutions:
x2=π6 and x2=5π6-->
a. x2=π6 --> x=π3
b. x2=5π6 --> x=5π3
Answers for [0,2π):
π3,π,5π3