How to find the asymptotes of f(x)= 0.72^x -2f(x)=0.72x2?

1 Answer
Mar 26, 2016

y=-2y=2
I have invited another mathematician to check this

Explanation:

Given:" "f(x)=0.72^x-2 f(x)=0.72x2

There are three prime conditions for this expression

Condition 1: x>0x>0

Condition 2: x<0x<0

Condition 3: x=0x=0
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Consider condition 3 ")x=0Consider condition 3 x=0

When x=0" "f(x)x=0 f(x) is defined as it has a definite value.

Thus color(blue)(x=0 " is NOT an asymptote")x=0 is NOT an asymptote
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Consider condition 2 ") x<0Consider condition 2 x<0

The f(x)f(x) takes the form 1/(0.72^x)-210.72x2

When x=0": "f(x)=1-2" "x=0: f(x)=12 thus defined

As xx becomes bigger 0.72^20.722 becomes smaller so

1/(0.72^2)" "10.722 becomes bigger

Thus lim_(xtooo) f(x)->oo (infinity is not a number!)

color(brown)("Is this an asymptote? I have invited another mathematician to look at this bit!")
Gut feeling is that this is NOT an asymptote!!!!!
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Consider condition 1 ") x>0

As x becomes increasingly larger 0.72^x becomes increasingly smaller and smaller.

So lim_(xtooo) 0.72^x-2 -> -2color

color(blue)(-2" Is an asymptote")