How to find the asymptotes of $Q (x) = \frac{2 x^{2}}{x^{2} - 5 x - 6}$ $Q(x) = (2x^2) / (x^2 - 5x - 6)$ ?

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Answer 1 · 2016-01-03T01:16:02

First, factor the denominator ...

$x^{2} - 5 x - 6 = (x - 6) (x + 1)$ $x^2-5x-6=(x-6)(x+1)$

Vertical asymptotes when the denominator is equal to zero ...

$x = 6 or x = - 1$ $x=6 or x=-1$

Horizontal asymptote : $y = \frac{2 x^{2}}{x^{2}} = 2$ $y=(2x^2)/x^2=2$

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How to find the asymptotes of Q(x) = (2x^2) / (x^2 - 5x - 6)Q(x)=2x2x2−5x−6Q(x) = (2x^2) / (x^2 - 5x - 6)?