How to find the value of x where $0<=x<=360^@$ for $sec x=1.0222$ ?

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Answer 1 · 2015-06-23T03:46:12

Find x knowing sec x = 1.0222

cos x = 1/1.0222 = 0.978

Calculator gives: cos x = 0.978 -> x = 11.96 deg

How to find the value of x where 0<=x<=360^@0<=x<=360^@ for sec x=1.0222sec x=1.0222?