How to find the value of x where $0<=x<=360^@$ for $sec x= -1.7172$ ?

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Answer 1 · 2015-05-21T13:13:45

$sec x = 1/cos x = -1.7172$

$cos x = 1/(-1.7172) = -0.58$

Calculator and trig unit circle give: $x = +-125.45 deg$

How to find the value of x where 0<=x<=360^@0<=x<=360^@ for sec x= -1.7172sec x= -1.7172?