How to find the x and y-intercepts of the following?

#(i) 9x^2=y^2#
#(ii) y^2-xy=0#

Also plot their graphs.

1 Answer
Aug 29, 2017

Both have #0# intercepts on #x#-axis and #y#-axis.

Explanation:

Remember to find #x#-intercept, put #y=0# and to find #y#-intercept, put #x=0#.

(i) In #9x^2=y^2#, if #y=0#, we have #x=0# and if #x=0# we have #y=0# and hence intercepts on both the axes are #0#. Below is given the graph for the same. Note that it is equivalent to #(3x+y)(3x-y)=0# and hence represents two lines #3x+y=0# and #3x-y=0#.

graph{9x^2=y^2 [-5, 5, -2.5, 2.5]}

(i) #y^2-xy=0#, if #y=0#, we have #x=0# and if #x=0# we have #y=0# and hence in this case too intercepts care #0#. Note that it is equivalent to #y(y-x)=0# and hence represents two lines #y=0# i.e. #x#-axis and #y=x#.

graph{y^2-xy=0 [-5, 5, -2.5, 2.5]}