How to find the y-intercept given $x^{2} + 14 + 1$ $x^2+14+1$ ?

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Answer 1 · 2015-05-15T17:54:06

Please check your question. y = x^2 + 14x + 1 ?

Answer 2 · 2015-05-15T18:02:31

Possibility 1
Assuming your equation is
$y = x^{2} + 14 + 1$ $y = x^2 + 14 +1$
then
$y = x^{2} + 15$ $y = x^2+15$

The y-intercept is the value of $y$ $y$ when $x = 0$ $x=0$
So the y-intercept in this case would be $15$ $15$

Possibility 2 (you meant $14 x$ $14x$ )
$y = x^{2} + 14 x + 1$ $y=x^2+14x+1$

Again, the y-intercept is the value of $y$ $y$ when $x = 0$ $x=0$
So, in this case, the y-intercept is $1$ $1$

How to find the y-intercept given x2+14+1x^2+14+1?