How to solve this ???

enter image source here

1 Answer
Jun 3, 2017

We have a=1 and b=2. For details please see below.

Explanation:

We have 3x2+6x+5

= 3(x2+2x)+5

= 3(x2+2×x×1+12)3×12+5

= 3(x+1)23+5

= 3(x+1)2+2

Hence a=1 and b=2

As (x+1)2 is a perfect square, and minimum value of 3x2+6x+5 is 2 and hence it is always non-zero and positive and hence 23x2+6x+50

3(x+1)20 or 3(x+1)2+22

i.e. 3x2+6x+52 and dividing by 3x2+6x+5, we get

023x2+6x+51
graph{2/(3x^2+6x+5) [-10, 10, -5, 5]}