Question

How to solve this equation in `[0,2pi]`? `min{sinx,cosx}=pi/4`.

Answer 1

See below.

Explanation:

Plotting `y_1=min(sinx,cosx)` in blue and `y_2=pi/4` in red, we see clearly that no intersection is possible. So no real solution for the equation

`min(sinx,cosx)=pi/4`