How to solve this integral #int 3/(x+1)^2 sqrt((x-1)/(x+1)) \ dx#?
#3/(x+1)^2# #sqrt((x-1)/(x+1))#
1 Answer
Jun 12, 2018
Please see below.
Explanation:
Seeing
Let
# = 3/2int u^(1/2) du = 3/2 2/3 u^(3/2) +C = u^(3/2) +C#
# = ((x-1)/(x+1))^(3/2) +C#
Check this answer by differentiating to make sure we get the original integrand.