How to transform 3x+6y=12 into intercept form? Using the formula #x/a + y/b = 1# ?

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Answer 1 · 2018-01-27T07:32:20

See below

# 3x + 6y = 12#

Divide the equation by 12.

# 3/12 x + 6/12 y = 12/12#

# (cancel3^1)/(cancel12^4)x + (cancel6^1)/(cancel12^2)y = (cancel12^1)/(cancel12)#

# x/4 + y/2 = 1# ----(1)

It is in the form of

#x/a + y/b = 1#

On equation a = 4

b = 2

Equation (1) is the intercept form.