How to verify the following identity?

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How to verify the following identity?

$\frac{cos x - cos y}{sin x + sin y} + \frac{sin x - sin y}{cos x + cos y} = 0$ $(cosx-cosy)/(sinx+siny)+(sinx-siny)/(cosx+cosy)=0$

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Answer 1 · 2018-07-17T15:54:42

$\frac{(cos x - cos y) (cos x + cos y) + (sin x - sin y) (sin x + sin y)}{(sin x + sin y) \cdot (cos x + cos y)}$ ${(cosx-cosy)(cosx+cosy)+(sinx-siny)(sinx+siny)}/{(sinx+siny)*(cosx+cosy)$

$\frac{1 - {cos}^{2} y - {sin}^{2} y}{(sin x + sin y) (cos x + cos y)}$ $(1-cos^2y-sin^2y)/{(sinx+siny)(cosx+cosy)$

$\frac{{sin}^{2} y - {sin}^{2} y}{(sin x + sin y) (cos x + cos y)}$ $(sin^2y-sin^2y)/{(sinx+siny)(cosx+cosy)$

$The numerator becomes 0 and anything divided upon 0 is 0$ $color(red)"The numerator becomes 0 and anything divided upon 0 is 0"$

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How to verify the following identity?

$\frac{cos x - cos y}{sin x + sin y} + \frac{sin x - sin y}{cos x + cos y} = 0$ $(cosx-cosy)/(sinx+siny)+(sinx-siny)/(cosx+cosy)=0$

1 Answer

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Science

Math

Humanities

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How to verify the following identity?

cosx−cosysinx+siny+sinx−sinycosx+cosy=0(cosx-cosy)/(sinx+siny)+(sinx-siny)/(cosx+cosy)=0

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$\frac{cos x - cos y}{sin x + sin y} + \frac{sin x - sin y}{cos x + cos y} = 0$ $(cosx-cosy)/(sinx+siny)+(sinx-siny)/(cosx+cosy)=0$