Question

How to write an equation for a rational function with: vertical asymptotes at x = 3 and x = -5?

Answer 1

`f(x) = 1/(x^2+2x-15)`

Explanation:

Function must be undefined at `x=3` and `x=-5`, i.e. `f(x) = 1/0`

Many functions will work but here is the simplest one:

`f(x) =1/((x-3)(x+5))`

`f(x) = 1/(x^2+2x-15)`

graph{1/(x^2+2x-15) [-10, 10, -5, 5]}