How would you balance the following chemical equation: $K C l O_{3} \to K C l + O_{2}$ $KClO_3 -> KCl + O_2$ ?

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How would you balance the following chemical equation: $K C l O_{3} \to K C l + O_{2}$ $KClO_3 -> KCl + O_2$ ?

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Answer 1 · 2016-07-20T22:17:59

$2 K C l O_{3} \to 2 K C l + 3 O_{2}$ $2KClO_3 -> 2KCl + 3O_2$

Explanation:

Given unbalanced equation:

$K C l O_{3} \to K C l + O_{2}$ $KClO_3 -> KCl + O_2$

Since the number of oxygens on the right hand side is even, we need a multiplier on the left hand side which is a multiple of $2$ $2$ .

We find that $2$ $2$ is sufficient, resulting in a total of $6$ $6$ oxygens on the left hand side, requiring a multiplier $3$ $3$ for the $O_{2}$ $O_2$ on the right hand side, etc.

$2 K C l O_{3} \to 2 K C l + 3 O_{2}$ $2KClO_3 -> 2KCl + 3O_2$

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How would you balance the following chemical equation: $K C l O_{3} \to K C l + O_{2}$ $KClO_3 -> KCl + O_2$ ?

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Explanation:

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How would you balance the following chemical equation: $K C l O_{3} \to K C l + O_{2}$ $KClO_3 -> KCl + O_2$ ?