How would you balance the following equation: Na2CO3 + BaCl2 --> NaCl + BaCO3?

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How would you balance the following equation: Na2CO3 + BaCl2 --> NaCl + BaCO3?

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Answer 1 · 2015-11-09T00:52:08

$N a_{2} C O_{3} + B a C l_{2} \to 2 N a C l + B a C O_{3}$ $Na_2CO_3+BaCl_2->2NaCl+BaCO_3$

Explanation:

It is important to notice that the $C O_{3}^{2 -}$ $CO_3^(2-)$ is a polyatomic ion, known as the carbonate ion. When balancing equations with polyatomic ions you can consider them to be a single entity.

On the reactant side you have:
2 $N a$ $Na$
1 $C O_{3}$ $CO_3$ ion
1 $B a$ $Ba$
2 $C l$ $Cl$

By placing 2 moles on the product side you conserve the mass of both $N a$ $Na$ and $C l$ $Cl$ .

Since there is one $C O_{3}$ $CO_3$ ion and one $B a$ $Ba$ you don't need to worry about their stoiciometric coefficient.

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How would you balance the following equation: Na2CO3 + BaCl2 --> NaCl + BaCO3?

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