How would you balance this chemical equation? $A s_{2} O_{3} + N a O H \to N a_{3} A s O + H_{2} O$ $As_2O_3 + NaOH -> Na_3AsO + H_2O$ ?

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How would you balance this chemical equation? $A s_{2} O_{3} + N a O H \to N a_{3} A s O + H_{2} O$ $As_2O_3 + NaOH -> Na_3AsO + H_2O$ ?

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Answer 1 · 2017-05-03T05:29:54

$A s_{2} O_{3} + 6 N a O H = 2 N a_{3} A s O_{3} + 3 H_{2} O$ $As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O$

Explanation:

It misses the subscript 3 for the Oxygen of the salt in the second member of the equation. In the first member Arsenic has Oxidation number = 3 and it can't change with reacting with NaOH. The correct reaction is the formation of a salt by reaction of NaOH with an acid oxide
$A s_{2} O_{3} + 6 N a O H = 2 N a_{3} A s O_{3} + 3 H_{2} O$ $As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O$

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How would you balance this chemical equation? $A s_{2} O_{3} + N a O H \to N a_{3} A s O + H_{2} O$ $As_2O_3 + NaOH -> Na_3AsO + H_2O$ ?

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How would you balance this chemical equation? As2O3+NaOH→Na3AsO+H2OAs_2O_3 + NaOH -> Na_3AsO + H_2O?

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How would you balance this chemical equation? $A s_{2} O_{3} + N a O H \to N a_{3} A s O + H_{2} O$ $As_2O_3 + NaOH -> Na_3AsO + H_2O$ ?