How would you balance this equation: ?Pb(NO_3)_2 → ?Pb + ?NO_2 + ?O_2?Pb(NO3)2→?Pb+?NO2+?O2?

1 Answer
Professor Sam
Mar 14, 2017

Pb(NO_3)_2 rarr Pb + O2 + 2NO_2Pb(NO3)2→Pb+O2+2NO2

Explanation:

To balance this reaction first we have to see the number of moles of each element.

Pb(NO_3)_2 rarr Pb + O_2 + NO_2Pb(NO3)2→Pb+O2+NO2

(Pb = 1) (Pb = 1)

(N = 2)(N=2) (O = cancel(4)^6)

(O = 6 ) (N = cancel(1)^2)

First try adding 3 as the coefficient in front of O_2 and 2 in front of NO_2 but that will be wrong as 2NO2 has 4 oxygen atoms which we dont have, so to make a balanced equation we must remove 3 from O2 and add 2 in front of NO_2

= Pb(NO_3)_2 rarr Pb + O2 + 2NO_2

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