How would you determine the oxidation number of Sulpher in $S O_{3}^{- 2}$ $SO_3^-2$ ?

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How would you determine the oxidation number of Sulpher in $S O_{3}^{- 2}$ $SO_3^-2$ ?

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Answer 1 · 2016-06-23T09:54:19

The oxidation state of sulfur in $S O_{3}^{2 -}$ $SO_3^(2-)$ is $+ I V$ $+IV$ .

Explanation:

The sum of the oxidation numbers/states of the individual elements in the species must equal the charge on the ion. $O$ $O$ normally takes a $- I I$ $-II$ oxidation state and it does here.

Thus $- 2 = 3 \times (- 2) + O N_{sulfur}$ $-2=3xx(-2)+ON_"sulfur"$

And so $O N_{sulfur} = - 2 + 6 = + 4,$ $ON_"sulfur"=-2+6=+4,$ i.e. $+ I V$ $+IV$ .

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How would you determine the oxidation number of Sulpher in $S O_{3}^{- 2}$ $SO_3^-2$ ?

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