How would you draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base?

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How would you draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base?

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Answer 1 · 2016-07-22T07:51:01

$H_{3} C - C H_{2} C (= O) O H + N a O H \to H_{3} C - C H_{2} C (= O) O^{-} N a^{+} + H_{2} O$ $H_3C-CH_2C(=O)OH + NaOH rarr H_3C-CH_2C(=O)O^(-)Na^+ + H_2O$

Explanation:

This is a standard acid base reaction. Propanoic acid is fairly weak, yet will react with sodium hydroxide. Sodium propanoate would give a basic solution in aqueous solution. Why?

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How would you draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base?

1 Answer

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