How would you find the slope of the line (2, 6), and (0, 2)?

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Answer 1 · 2016-10-05T14:55:59

$(y_2-y_1)/(x_2-x_1)=(2-6)/(0-2)=(-4)/-2=2=m$

$(2,6) => (x_1,y_2)$

$(0,2) => ((x_1,y_2))$

Slope formula

$(y_2-y_1)/(x_2-x_1)=(2-6)/(0-2)=(-4)/-2=2=m$

Answer 2 · 2016-10-05T15:02:33

Slope of line joining $(2,6)$ and $(0,2)$ is $2$

Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is

$(y_2-y_1)/(x_2-x_1)$

hence slope of line joining $(2,6)$ and $(0,2)$ is

$(2-6)/(0-2)=(-4)/(-2)=2$