How would you graph #f(x)= 2 ln x#?

1 Answer
Jan 21, 2016

See the explanantion

Explanation:

To find the x-intercept mathematically

If #y=2ln(x)# then #ln(x)=y/2#

Another way of writing this is:

#e^(y/2)=x#.......................................(1)

The x-intercept is when #y=0# so equation (1) becomes:

#e^(0/2)=e^0=1=x#

So the x-intercept is at #x=1#
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You asked 'how' would you graph ....

The method would be to build a table of values.
The top row would have the values of x
The next row down would have the values of ln(x)
and the row below that would have the values of #2xxln(x)#

This last row gives the values for #y#

You would then mark a series of points that maches both your value of #x# and the calculated value of #y#

Your graph should look something like this:
Tony B