How would you graph this parabola? #y=(x+1)^2-3#

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Answer 1 · 2018-07-13T17:56:16

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Please read the explanation,

#" "#
We are given the quadratic equation: #color(red)(y=f(x)=(x+1)^2-3#

Generate a Data table of values as shown below:

enter image source here

Observing the data table, we can easily see that #color(red)([-1"," -3]]#

Also observe that the quadratic function is in Vertex Form:

#color(red)(y = f(x) = a(x-h)^2+k#, where

#color(red)((h,k)# is the Vertex of the Parabola.

We observe that #color(blue)(h=-1 and k=-3)#

Hence, Vertex is at : #color(blue)([-1"," -3]#

Examine the graph below:

enter image source here

Hope it helps.