How would you identify the acid, base, conjugate acid and conjugate base in the following reaction: HCN + SO4^(2-) --> HSO4^(-) + CN^(-)?

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How would you identify the acid, base, conjugate acid and conjugate base in the following reaction: HCN + SO4^(2-) --> HSO4^(-) + CN^(-)?

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Answer 1 · 2015-11-22T20:50:48

Acid, hydrogen cyanide, "Prussic" acid; base, sulfate ion. The conjugate species is idenitified by proton addition OR removal.

Explanation:

Acid, $H - C \equiv N$ $H-C-=N$ ; conjugate base, $N \equiv C^{-}$ $N-=C^-$ , cyanide anion.

Base, $S O_{4}^{2 -}$ $SO_4^(2-)$ , sulfate ion; conjugate acid. $H S O_{4}^{-}$ $HSO_4^-$ .

The conjugate acid is simply the starting material PLUS a proton; the conjugate base is simply the starting material MINUS a proton. Both mass and charge are conserved. SO the conjugate base of sulfuric acid, $H_{2} S O_{4}$ $H_2SO_4$ , is $H S O_{4}^{-}$ $HSO_4^-$ , and the conjugate base of this anion is $S O_{4}^{2 -}$ $SO_4^(2-)$ .

What is the conjugate acid of sulfuric acid, $H_{2} S O_{4}$ $H_2SO_4$ ? I assure you that it exists.

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How would you identify the acid, base, conjugate acid and conjugate base in the following reaction: HCN + SO4^(2-) --> HSO4^(-) + CN^(-)?

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