How would you prepare 500.0 mL of a 2.00 mol/L solution of HCI from a concentrated solution of 12.0 mol/L?

1 Answer
anor277
Aug 22, 2017

Carefully, and we adds acid to water. This is an important practical difficulty......

Explanation:

In fact the most concentrated hydrochloric acid you can buy is approx. 32% w/w, and this is about 10.6⋅mol⋅L−1. Anyway we will go with the terms of the question.

Here we use the ratio, concentration=moles of solutevolume of solution.

And thus moles of solute=concentration×volume.

We want 500.0×10−3⋅L×2.00⋅mol⋅L−1=1⋅mol with respect to HCl.

And so we take the quotient, 1.00⋅mol12.0⋅mol⋅L−1×103⋅mL⋅L−1

=83.3⋅mL.

And so we take 83.3⋅mL of conc. acid, and we add approx. 420⋅mL of water. The order of addition is VERY important.

Remember what I said about diluting conc. acid: If you spit in acid it spits back.

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