Question

HT bisects DG at O. If HO=3x+17, TO=4x-2, DO= 3x+10 and GO= 6x-20, how do you find the value of x?

Answer 1

`x=10`

Explanation:

`HT` is the perpendicular bisector of `DG` which means that
`DO = OG`

`DG` is not automatically the bisector of `HT`, so you do NOT know that `HO= OT`

Find `x` if `OG = DO`

`6x-20 = 3x+10`

`6x-3x=10+20`

`3x =30`

`x =10`