Hydrogen and oxygen react chemically to form water. How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

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Hydrogen and oxygen react chemically to form water. How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

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Answer 1 · 2016-09-05T06:24:12

Approx. $36 \cdot g$ $36*g$

Explanation:

We need a stoichiometric equation for water synthesis:

$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l)$ $H_2(g) + 1/2O_2(g) rarr H_2O(l)$

Clearly, dihydrogen must be present in a 2:1 molar ratio with respect to dioxygen.

$Moles of dihydrogen$ $"Moles of dihydrogen"$ $=$ $=$ $\frac{4.8 \cdot g}{2.01 \cdot g \cdot m o l^{- 1}}$ $(4.8*g)/(2.01*g*mol^-1)$ $=$ $=$ $2.39 \cdot m o l$ $2.39*mol$

$Moles of dioxygen$ $"Moles of dioxygen"$ $=$ $=$ $\frac{38.4 \cdot g}{32.0 \cdot g \cdot m o l^{- 1}}$ $(38.4*g)/(32.0*g*mol^-1)$ $=$ $=$ $1.2 \cdot m o l$ $1.2*mol$

Given these molar quantities (they are approx. 2:1) the gases are present in stoichiometric proportion. $2$ $2$ $m o l$ $mol$ water are going to be produced.

$2 \cdot m o l \times 18.00 \cdot g \cdot m o l^{- 1}$ $2*molxx18.00*g*mol^-1$ $=$ $=$ $36 \cdot g$ $36*g$

Do you think that this would be an exothermic reaction; i.e. do you think that energy would be released by the reaction?

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Hydrogen and oxygen react chemically to form water. How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

1 Answer

Explanation:

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