I have done half but i am not able to find angle in part2?

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I have done half but i am not able to find angle in part2?

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Answer 1 · 2018-07-24T12:09:38

$θ = 0^{\circ}, - {109.5}^{\circ}, {109.5}^{\circ}$ $theta = 0^circ, -109.5^circ, 109.5^circ$

Explanation:

Continuing from the factored equation

$(3 cos θ + 1) (cos θ - 1) = 0$ $(3costheta+1)(costheta-1) = 0$

Either $cos θ = - \frac{1}{3}$ $costheta = -1/3$ or $cos θ = 1$ $costheta = 1$ .

Solving $cos θ = 1$ $costheta = 1$ :

Remember that $cos θ$ $costheta$ is an even function, so $cos (- θ) = cos θ$ $cos(-theta) = costheta$ . Essentially, if we find $θ$ $theta$ that satisfies the equation, $- θ$ $-theta$ will also satisfy it.

$cos θ = 1$ $costheta = 1$

$θ = \pm 0^{\circ} = 0^{\circ}$ $theta = +-0^circ = 0^circ$

Solving $cos θ = - \frac{1}{3}$ $costheta = -1/3$ :

$cos θ = - \frac{1}{3}$ $costheta = -1/3$

$θ \approx \pm {109.5}^{\circ}$ $theta ~~ +-109.5^circ$

The three solutions to the equation are $θ = 0^{\circ}, - {109.5}^{\circ}, {109.5}^{\circ}$ $theta = 0^circ, -109.5^circ, 109.5^circ$ .

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I have done half but i am not able to find angle in part2?

1 Answer

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