I use a cosmetic mirror to magnify my eyelashes. My 1.2-cm long eyelashes are magnified to 1.6 cm when placed 5.8 cm from the mirror, how can I determine the image distance for such an upright image?

1 Answer
Jan 24, 2015

-7.73 cm, negative meaning behind the mirror as a virtual image.
Graphically your situation is:
enter image source here
Where:
#r# is the radius of curveture of your mirror;
#C# is the centre of curvature;
#f# is the focus (=#r/2#);
#h_o# is the object height #=1.2 cm#;
#d_o# is the object distance #=5.8 cm#;
#h_i# is the image height #=1.6 cm#;
#d_i# is the image distance #=?#;

I use the magnification #M# of the mirror to relate my parameters as:
#M=h_i/(h_o)=-d_i/(d_o)#
Or:
#1.6/1.2=-d_i/5.8# and

#d_i=-7.73 cm#